Question 165215
For log rules see:
http://www.purplemath.com/modules/logrules.htm
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log(base 3)(x+8) + log(base 3)(x) = 2 
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Applying log rule: logb(mn) = logb(m) + logb(n)
log(base 3)(x^2+8x) = 2 
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Applying log rule: logb(m) = n  =>> m = b^n
x^2+8x = 3^2
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x^2+8x = 8
x^2+8x-8 = 0
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Since we can't factor, use the quadratic equation.  Doing so will yield:
x = {0.899, -8.899}
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Details of quadratic:
*[invoke quadratic "x", 1, 8, -8 ] = 0