Question 165103
Let x be a side of square a.
2x is the length of a side of square b.
3x is the length of a side of square c.
A[a]=x^2
A[b]=(2x)^2=4x^2
A[c]=(3x)^2=9x^2
9x^2/(x^2+4x^2)
=9x^2/5x^2
=9/5
=1.8
So, the area of triangle C is 80% greater than the sum of the areas of triangles A and B.
.
Ed