Question 165086
(pounds of fat in mixture)/(total pound of mixture) = per cent fat
Let {{{n}}} = pounds of no-fat yogurt to be used
{{{60 - n}}}= pound of 3% yogurt used
The only fat is in the 3% yogurt
{{{.03*(60 - n) / 60 = .01}}}
{{{(1.8 - .03n) / 60 = .01}}}
{{{1.8 - .03n = .6}}}
{{{.03n = 1.2}}}
{{{n = 40}}}
{{{60 - 40 = 20}}}
40 pounds of no-fat yogurt and 20 pounds of 3% fat yogurt are needed
check:
{{{.03*(60 - n) / 60 = .01}}}
{{{.03*(60 - 40) / 60 = .01}}}
{{{.6/60 = .01}}}
{{{.01 = .01}}}