Question 165004
It's correct.
It can be solved by either using the quadratic formula or completing square.
{{{x^2+6x-4=0}}}
{{{x^2+6x=4}}}
{{{x^2+6x+9=4+9}}}
{{{x^2+6x+9=13}}}
{{{(x+3)^2=13}}}
So
{{{x+3 = sqrt(13)}}}
or {{{x+3=-sqrt(13)}}}
Thus the roots are:
{{{x=-3+sqrt(13)}}}
{{{x=-3-sqrt(13)}}}