Question 164935
ok, the first thing that you need to do is get the formula in slope-intercept form. {{{y=mx+b}}} where (x,y) is a coordinate; m=slope; b=the y-intercept
Given: x=1/2y+1 
       x-1=1/2y   subtract 1 from both sides
       2(x-1)=y   multiply both sides by 2
or     y=2(x-1)   Identity
       y=2x-2     distribute the 2 
       y=mx+b
now it is in slope-intercept form

so now we know that the slope of the original line is 2 and the y-intercept of the original line is -2
a line that is parallel to this one is going to have the same slope as this line. so the new line will be y=2x+b  

We know that the line must go through the points (1,-2)
so plug these points in and solve for b
 y  =2 x +b
(-2)=2(1)+b plug in points x=1 y=-2
 -2 =2+b    simplify
  -4=b      subtract 2 from each side
now plug in the slope(m) and the y-intercept(b) of the new line into the slope intercept form and you get:

{{{y=2x-4}}}
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