Question 164914
x^2+4x+3=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(-4+-sqt[4^2-4^2-4*1*3])/2*1
x=(-4+-sqrt16-12)/2
x=(4+-sqrt4)/2
x=(4+-2)/2
x=(4+2)/2
x=6/2=3 answer.
x=(4-2)/2
x=2/2=1 answer.