Question 164905
 the equation would be as follows: A+2(1/A)=3 where A is the varible we are looking for.  multiply each term by A and we get A^2+2=3A ... now subtract 3A from each side we end up with A^2-3A+2=0  which factors into (A-2)(A-1)=0  setting A-2=0 and A-1=0 we come up with the solution set of  A=1,2  

answer: 1 and 2