Question 164834
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First, let's compute to have an ave. of 70:
{{{(2/3)MT+(1/3)FE=70}}}
{{{(2/3)(48)+(1/3)(FE)=70}}}
{{{(96/3)+(1/3)(FE)=70}}}
{{{(1/3)FE=70-(96/3)=70-(cross(96)32/cross(3))}}}
{{{(1/3)FE=70-32=38}}}, cross multiply
{{{FE=38*3=114}}}
Next, ave. of 79:
{{{(2/3)(48)+(1/3)FE=79}}}
{{{(96/3)+(1/3)FE=79}}}
{{{(1/3)FE=79-(96/3)=79-(cross(96)32/cross(3))}}}
{{{(1/3)FE=79-32=47}}}, cross multiply
{{{FE=47*3=141}}}
Therefore, the Final Exam should be in the range of {{{highlight(114-141)}}} to have an average of 70-79 inclusive. 
thank you,
Jojo</pre>