Question 164824
lets call the numbers a and b with a being the larger and b the smaller. 
5a+3b=47 and 4a-2b=20 you can solve by substitution or similtaneously.  I will solve by substitution  take the 1st formula and solve for a or b.  I will solve for a  so subtract 3b from each side and then divide by 5 and you get 
a=(47-3b)/5 now substituting this for a in the 2nd formula we get (4(47-3b)/5)
-2b=20 if we multiply each term by 5 we get 4(47-3b)-10b=100  multiplying we get 188-12b-10b=100  simplify 22b=88 b=4  substituting in any original equation(I pick the 1st one we get 5a+3(4)=47 so 5a= 35 therefore a = 6

answer larger number  a=6
       smaller number b=4