Question 164673
Let N be the first odd integer.
The next 3 consecutive integers are N+2, N+4, and N+6.
{{{N+(N+2)+(N+4)+(N+6)=-80}}}
{{{4N+12=-80}}}
{{{4N=-92}}}
{{{N=-23}}}
The four integers are then -23,-21,-19,-17.