Question 22051
{{{(-9p^3*q^2)*(-3p^2*q^4) }}}

First of all, let's just look at the numbers.  -9 · -3 = 27.  So now our problem is down to this:

{{{27(p^3*q^2)*(p^2*q^4) }}}

And now, when you multiply terms with the same base, you add their exponents.  So notice that we have two bases, p and q.  If we gather the terms together, we have

{{{27(p^3*p^2)*(q^2*q^4) }}}

So if we add exponents, we get

{{{27p^5*q^6}}}

Hope that helps