Question 164440


{{{36x^2-4y^2}}} Start with the given expression.



{{{(6x)^2-4y^2}}} Rewrite {{{36x^2}}} as {{{(6x)^2}}}.



{{{(6x)^2-(2y)^2}}} Rewrite {{{4y^2}}} as {{{(2y)^2}}}.



Notice how we have a difference of squares. So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{(6x+2y)(6x-2y)}}} Factor the expression using the difference of squares.



So {{{36x^2-4y^2}}} factors to {{{(6x+2y)(6x-2y)}}}.



In other words {{{36x^2-4y^2=(6x+2y)(6x-2y)}}}.