Question 23334
If it asks you for a y value for a given x value, all you have to do is plug it in.

So for {{{y=1/(x-1)}}}, 

when x = -2, y = 1/(-2-1) = 1/(-3) = -1/3
when x = -1, y = 1/(-1-1) = 1/(-2) = -1/2
when x = 0, y = 1/(0-1) = 1/(-1) = -1
when x = 1, y = 1/(1-1) = 1/0 <--undefined.  Cannot divide by zero.
when x = 2, y = 1/(2-1) = 1/1 = 1
when x = 3, y = 1/(3-1) = 1/2