Question 23326
3x-x^2>0
-3x+x^2<0
x(x-3)<0
either x>0 & x-3<0 => x>0 & x<3 => 0 < x < 3
or x<0 & x-3>0 => x<0 & x>3 => can not be true
hence,
0 < x < 3 is the answer