<PRE><B>Question 164196</B>
Assume the problem is:
x ={{{1/8}}}y - 1
y ={{{1/4}}}x + 39
;
Get rid of the denominators, multiply the 1st equation by 8, 2nd equation by 4
8x = y - 8
4y = x + 156
:
Rearrange the 1st equation for substitution
y = (8x + 8)
:
Substitute (8x+8) for y in the 2nd equation
4(8x+8) = x + 156
:
32x + 32 = x + 156
:
32x - x = 156 - 32
;
31x = 124
x = {{{124/31}}}
x = 4
:
Find y using eq: y ={{{1/4}}}x + 39
y ={{{1/4}}}*4 + 39
y = 1 + 39
y = 40
:
:
Check solutions in the 1st equation: x ={{{1/8}}}y - 1
4 ={{{1/8}}}*40 - 1
4 = 5 - 1</PRE>