Question 164115
Assume the problem is:
{{{1/4}}} = 3- {{{((2x-1))/((x+2))}}}
Multiply equation by 4(x+2) to get rid of the denominators
4(x+2)*{{{1/4}}} = 4(x+2)*3- 4(x+2)*{{{((2x-1))/((x+2))}}}
cancel out the denominators and you have:
x + 2 = 12(x+2) - 4(2x-1)
:
x + 2 = 12x + 24 - 8x + 4
:
x + 2 = 4x + 28
;
2 - 28 = 4x - x
:
-26 = 3x
x = {{{-26/3}}}
;
:
I'll let you check the solution in the original equation