Question 164311
The width of a rectangle is 22 centimeters shorter that its length. The perimiter of the rectangular is 160. find its length.

let w be the width and L be the length(both in centemeters).

The width of a rectangle is 22 centimeters shorter that its length.
converting this into an equation you get
w = L - 22

The perimiter of the rectangular is 160. find its length.
converting this into an equation you get
2L + 2w(equation of the perimeter of a rectangle) = 160

now we substitute the first equation into the second one and solve for the length.

2L + 2w = 160
2L + 2(L - 22) = 160
2L + 2L -44 = 160
4L -44 = 160
4L = 204
L = 51