Question 164225
Remember {{{i=sqrt(-1)}}}


{{{ sqrt(-50) - sqrt(-8)=sqrt(25)*sqrt(-1)*sqrt(2)-sqrt(4)*sqrt(-1)*sqrt(2)=5i*sqrt(2)-2i*sqrt(2)=(5i-2i)*sqrt(2)=3i*sqrt(2)}}}



So {{{ sqrt(-50) - sqrt(-8)=3i*sqrt(2)}}} which is now in {{{a+bi}}} form where {{{a=0}}} and {{{b=3*sqrt(2)}}}