Question 164226
What you need to do is multiply by its conjugate pair to rationalize it:

{{{1/(2+3i) * (2-3i)/(2-3i)}}}

See that we are just multiplying by 1 in a special way.

{{{(2-3i) / (2+3i)(2-3i) = (2-3i) / (4-3i^2) = (2-3i) / 7 = 2/7 - 3i/7}}}