Question 164191
Hi-

Whenever we are given a function C(g) and g = some number n, this means that we plug the number n wherever g appears in the equation.
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So for your first problem, find C(2), we simply plug 2 into the C(g) equation whereever g is.  Since C(g) = 3.03*g,  then C(2) = 3.03*2 = 6.06.  So C(2) = 6.06.
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For the next problem, C(9) we plug 9 into g to get C(9) = 3.03 * 9 = 27.27.  So C(9) = 27.27
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I think you may be confusing C(g) to mean C * g.  Note that when we are writing a function C(g), then C(g) is said C OF g, not C times 6.  It may be a little confusing, but C is actually the name of the function, not a variable.  So you don't multiply C with anything!