Question 164192
Let:
first investment = x
second investment = 5400 - x


the two investments has the same amount of interest, so:
{{{(8/100) * x = (10/100) * (5400 - x)}}}
<=> 0.08x = 0.1*(5400 - x)
<=> 0.08x = 540 - 0.1x
<=> 0.08x + 0.1x = 540
<=> 0.18x = 540
<=> x = 540/0.18
<=> x = 3000


first investment = 3000
second investment = 5400 - 3000 = 2400


so you should invest $3,000 at 8% and $2,400 at 10%