Question 23319
4x-y=11
3x=3-y


In the second equation get it into standard form, by adding +y to each side:


4x-y=11
3x +y =3


Now, just add the two equations together:

7x = 14
x= 2


Next, substitute x =2 into EITHER equation.  The first will do.
4x-y = 11
4(2)- y = 11
8-y = 11
-y = 3
y = -3


The point of solution is (2,-3).


Check by substituting both values into the OTHER equation:
3x= 3-y
3(2) = 3-(-3)
6=6
It checks!


R^2 at SCC