Question 164095
1st integer = x
2nd integer = x+2
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x(x+2)=168
{{{x^2 + 2x = 168}}}
{{{x^2 + 2x-168=0}}}
(x+14)(x-12)=0
x+14=0
x=-14
x-12=0
x=12
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So we end up with 2 possibilities;
x = 12 or x = -14
Now we need our second;
x + 2 = 12+2=14
x+2 = -14+2=-12
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When x = 12, the second integer = 14
When x = -14, second integer = -12
:)