Question 164062
{{{x/3 = (4)/(x+1)}}}
Lets get rid of denominators;
multiply each side by 3 and x+1;
{{{x^2 + x = 12}}}
Now subtract 12 from both sides;
{{{x^2+x-12=0}}}
factor;
(x+4)(x-3)=0
x+4= 0 
x=-4
x-3=0
x=3
solution set = -4, 3
:)