Question 23311
This is a bit tricky.
A. Solve x^2+x=0 i.e. the equality .
   x(x+1)=0
   x = 0 or x= -1
Now, draw a number line and mark -1 and 0 on it.
You now see three segments on the line: one to
the left of -1, one between -1 and 0, and one
to the right of 0.

Now check the inequality  for a value in each
of the segments.  For example try -10,-1/2,10.
For x=-10, (-10)^2+(-10)>0 ?
            100 -10> 0 ?
                90 > 0 YES
Therefore the inequality is true for every value
of x<=1.
Do the same for x=-1/2 and for x=10.

You should find the solution is x<-10 or x>10

Cheers,
stan H.