<PRE><B>Question 163987</B>
Find the vertex, the line of symmetry, and the maximum or minimum of f(x). Graph the function 
f(x)=(1)/(5)(x+1)^2+9
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f(x) = (1/5)(x^2+2x+1)+9
f(x) = (1/5)x^2 + (2/5)x + (46/5)
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max or min occurs when x = -b/2a = -(2/5)/(2/5) = -1
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f(-1) = (1/5) -(2/5) + 46/5 = 45/5 = 9
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minumum occurs at (-1,9)
axis of symmetry is x = -1
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Graph:
{{{graph(400,300,-10,10,-10,30,(1/5)x^2+(2/5)x+(46/5))}}}
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Cheers,
Stan H.</PRE>