Question 163904
We have the following fractions:

3/(x + 1) + 2/(x - 1)

Do you recall how to add fraction with different denominators?

For example, if you have 2/3 + 4/5, what is the answer?

You can use the same method for adding regular fractions like 2/3 + 4/5 when adding the two given algebraic fractions.

OUR LCD = (x + 1)(x - 1)

We divide the LCD by each denominator and then we multiply the quotient by each numerator to find the sum.

Can you take it from here?

If not, write back and I will answer the question in full after work.

Your reply:

"I am not sure if I can answer this right or not!"

MY REPLY:

3/(x + 1) + 2/(x - 1)

Our LCD is (x+1)(x-1)

3/(x + 1) times (x+1)(x-1)= 3(x - 1) = 3x - 3

=============================================

2/(x -1) times (x+1)(x-1)= 2(x + 1) = 2x + 1

We now have this fraction over our LCD:

[3x - 3 + 2x + 1]/(x + 1)(x - 1)

We combine like terms in the numerator and that's it.

Final answer: (5x - 2)/(x + 1)(x - 1)