Question 163924
x^2-y^2 over 2x all over x+y over x^2
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[(x^2-y^2)/2x] / [(x+y)/x^2]

Invert the denominator and multiply:

[(x^2-y^2)/2x] * [x^2/(x+y)]

Cancel factors that are common to a numerator and a denominator,
such as (x+y), and x:

= [(x-y)/2] * [x/1]

= [x(x-y)/2]

Cheers,
Stan H.