Question 163898
{{{x/3=4/x+1}}}

multiply both sides by 3x:

{{{3x*(x/3)}}} = {{{3x*(4/x)+3x*1}}}

simplify:

{{{x^2}}} = 12 + 3x

{{{x^2 -3x -12}}} = 0

solve it using quadratic formula

x = {{{(3+sqrt(51))/2}}}

x = {{{(3-sqrt(51))/2}}}

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