Question 163867
1.{{{A-2B=16}}}
2.{{{B+3=3A}}}
Use eq. 2 to find an expression for B in terms of A.
2.{{{B+3=3A}}}
{{{B=3A-3}}}
Now substitute this expression into eq. 1 and solve for A,
1.{{{A-2B=16}}}
{{{A-2(3A-3)=16}}}
{{{A-6A+6=16}}}
{{{-5A=10}}}
{{{A=-2}}}
From eq. 2,
{{{B=3A-3}}}
{{{B=3(-2)-3}}}
{{{B=-6-3}}}
{{{B=-9}}}
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Check your answers using the equations.
1.{{{A-2B=16}}}
{{{-2-2(-9)=16}}}
{{{-2+18=16}}}
{{{16=16}}}
True.
2.{{{B+3=3A}}}
{{{-9+3=3(-2)}}}
{{{-6=-6}}}
True.
Good answers.