Question 163814
find the consecutive odd numbers such that twice the sum of the first and second is one more than three times the third.
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Let x = 1st consecutive odd number
then
x+2 = 2nd consecutive odd number
x+4 = 3rd consecutive odd number
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From: "twice the sum of the first and second is one more than three times the third" we get:
2(x + x+2) = 3(x+4)+1
2(2x+2) = 3(x+4)+1
4x+4 = 3x+12+1
4x+4 = 3x+13
x+4 = 13
x = 9 (1st number)
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2nd number:
x+2 = 9+2 = 11
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3rd number:
x+4 = 9+4 = 13
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Ans: 9, 11, 13