Question 163710
Let the three consecutive numbers be n-1, n, n+1.
As the sum of 3 consecutive integers is twice the smallest integer, we have
n - 1 + n + n + 1 = 2(n - 1)
Solving the equation, we obtain:
3n = 2n - 2
n = -2
So the smallest number is n-1=-2-1=-3
the middle number is n = -2
the largest number is n + 1 = -2 + 1 = -1
Thus the three consecutive numbers are -3, -2, -1.