Question 163741
i can do your first equation easy enough.
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(p^2 + 4p - 5)/(p-1)
you have to get the factors of the numerator.
usually one of those factors is equal to the denominator and they cancel out.
in this case that works out fine.
the factors of the numerator are (p+5)*(p-1)
substituting in the equation, we get
((p+5)*(p-1))/(p-1)
the p-1 cancels out and the equation becomes
p+5.
that's the answer for the first equation.
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second equation can be solved as well but i don't see any common factors that can be canceled out.
equation is
(p^2 + 7p + 10) / (p+4)
factors for the numerator are (p+2)*(p+5)
equation becomes
((p+2)*(p+5))/(p+4)
i can't see where it can be simplified further than that.