Question 163741
{{{(p^2 + 4p -5)/(p-1)}}}
Look closely at the numerator, notice you can factor that to
{{{((p+5)(p-1))/(p-1)}}}
now you can see the (p-1)'s cancel leaving 
(p + 5)
:
:
{{{(p^2 + 7p + 10)/(p+4)}}}
We can factor the numerator here too, but is not much help
{{{((p+2)(p+5))/(p+4)}}}
:
:
It occurs to me that this may be all one problem, 
then invert the dividing fraction and multiply:
(p+5) * {{{((p+4))/((p+2)(p+5))}}}
Cancel (p+5)'s and you have
{{{(p+4)/(p+2)}}}