Question 163727
Let x=one number
And y= the other number

x+y=5-----------eq1
x*y=9------------eq2
Divide both sides of eq2 by y
x=9/y---------------substitute into eq1

(9/y)+y=5 multiply each term by y
9+y^2=5y  subtract 5y from each side
y^2-5y+9=0 ----quadratic in standard form.  Solve using quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (5 +- sqrt(( -5)^2-4*1*9 ))/(2) }}} 

{{{x = (5 +- sqrt((25-36)))/(2) }}} 

{{{x = (5 +i*sqrt(11))/(2) }}} ------------------one number
{{{x = (5 -i*sqrt(11))/(2) }}} ----------the other number

CK
(5 +i*sqrt(11))/(2)+(5 -i*sqrt(11))/(2)=10/2=5
And
{(5 +i*sqrt(11))/(2)}*{(5 -i*sqrt(11))/(2)}=25/4 +11/4=36/4=9


Hope this helps---ptaylor