<PRE><B>Question 163676</B>
Tank A contains 3000 gallons of water and Tank B contains 1000 gallons of water.
 The water in tank A is being drained into Tank B at the rate of 3/2 gal/minute,
 while water leaks from Tank B at 1/2 gal/min. How long until Tank A has the
 same amount of water as Tank B?
:
Let t = time required for the two tanks to be equal (in minutes)
:
Use 1.5 for 3/2 and .5 for 1/2
:
3000 - drained = 1000 + added - drained
3000 - 1.5t = 1000 + 1.5t - .5t
:
3000 - 1.5t = 1000 + 1t
:
3000 - 1000 = 1.5t + 1t
:
2000 = 2.5t
t = {{{2000/2.5}}}
t = 800 min or: 800/60 = 13 hrs 20 min
:
 How much water does each tank contain then?
Replace t with 800 min
3000 - 1.5(800) =
3000 - 1200 = 1800 gal in tank 1
and
1000 + 1(800) = 1800 in tank 2

:
How about this? Did it make sense to you? Any questions?</PRE>