Question 21835
What you have so far is correct: {{{(y/x^3)/(x/y^2)}}}


Since you have done this, it really means:
{{{(y/x^3)}}} divided by {{{(x/y^2)}}} 


then you can invert the second fraction and multiply:

{{{(y/x^3)*((y^2)/x)}}} 
{{{(y^3)/(x^4)}}}


Having done this, it might have been easier if you had just subtracted the exponents:
{{{(x^-3*y^1)/(x^1*y^-2)}}}


{{{x^(-3-1)*y^(1-(-2))}}}


{{{x^-4 *y^3}}}
{{{(1/(x^4))*y^3}}}
{{{(y^3)/(x^4)}}}


R^2 at SCC