Question 163647

Complete the squares in both x and y.
Take 1/2 of both the x and y coefficient and square it.
Add that number to both sides of the equation. 
{{{(x^2+8x)+(y^2+6y)-24=0}}}
{{{(x^2+8x+16)+(y^2+6y+9)-24=16+9}}}
{{{(x+4)^2+(y+3)^2-24=25}}}
{{{(x+4)^2+(y+3)^2=49}}}
Compare this equation to a general form of a circle centered at (h,k) with a radius, R.
{{{(x-h)^2+(y-k)^2=R^2}}}
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This is an equation of a circle centered at (-4,-3) with a radius of 7.