Question 163631
equation is given as:
{{{(2x^2-3x+1)(4)(3x+2)^3(3)+(3x+2)^4(4x-3)}}}
first term that looks like it can be simplified is (2x^2-3x+1)
this simplifies to (2x-1)*(x-1)
equation becomes
{{{((2x-1)*(x-1)*4*(3x+2)^3*3)+((3x+2)^4*(4x-3))}}}
since 4*3 = 12, equation becomes
{{{(12*(2x-1)*(x-1)*(3x+2)^3)+((3x+2)^4*(4x-3))}}}
since (3x+2)^4 = (3x+2)^3*(3x+2), the equation can be further simplified as follows:
{{{((12*(2x-1)*(x-1))+((3x+2)*(4x-3))*(3x+2)^3)}}}
this might be a little hard to see, but if you let {{{a = 12*(2x-1)*(x-1)}}}
and you let {{{b = (3x+2)*(4x-3)}}}
and you let {{{c = (3x+2)^3}}}
the equation looks like
{{{(a+b)*c}}}
which is the same as
{{{(a*c)+(b*c)}}}
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hopefully this is what they are looking for.