Question 163613
Let's call our first integer, N.
Then the next three consecutive even integers would be N+2, N+4, and N+6.
Their sum is
{{{N+(N+2)+(N+4)+(N+6)<35}}}
{{{4N+12<35}}}}
{{{4N<23}}}
{{{N<5}}}
.
.
.
(4,6,8,10)
(2,4,6,8)
(0,2,4,6)
(-2,0,2,4)
.
.
.
The set of four consecutive even integers that sum to less than 35 is({{{N}}},{{{N+2}}},{{{N+4}}},{{{N+6}}}) where {{{N<=4}}}