Question 21841
I'm not sure exactly what you want to do with this because of that last = sign on the end of your problem.   If you really want to solve this equation:
{{{a^3b^3c^3 - a^2b^3c^4 = a^3b^2c^4}}}, then set it equal to zero:

{{{a^3b^3c^3 - a^2b^3c^4 - a^3b^2c^4=0}}}


and factor it by taking out the common factor of {{{a^2*b^2*c^3}}}
{{{a^2*b^2*c^3*(ab -bc - ac )=0}}}

This means that either a=0, or b= 0 , or c=0, or ab-bc-ac= 0.


I'm not sure if that is what you wanted to do.  Maybe we are not on the same frequency here.  If you had something else in mind, please re-post it.


R^2 at SCC