Question 163505
1. Correct
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2. Correct
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3. Correct
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4. Let's call pounds of cashews C, pounds of brazil nuts B.
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4a.{{{C+B=50}}}
4b.{{{6.75*C+5.00*B=5.75*(B+C)}}}
From eq. 4a, get an expression for C in terms of B.
4a.{{{C+B=50}}}
{{{C=50-B}}}
Now substitute that expression into eq. 4b and solve for B.
4b.{{{6.75*C+5.00*B=5.75*(50)}}}
{{{6.75*(50-B)+5.00*B=5.75*(50)}}}
{{{337.50-6.75B+5.00B=287.50}}}
{{{-1.75B=-50}}}
{{{B=200/7}}}
From eq. 4a,
4a.{{{C+B=50}}}
{{{C+200/7=350/7}}}
{{{C=150/7}}}
B=28.6 lbs, C=21.4 lbs.
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5.X-intercept : Let y=0 solve for x.
{{{5x-7y=35}}}
{{{5x-7(0)=35}}}
{{{5x=35}}}
{{{x=7}}}
X-intercept:(7,0)
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Y-intercept : Let x=0 solve for y.
{{{5x-7y=35}}}
{{{5(0)-7y=35}}}
{{{-7y=35}}}
{{{y=-5}}}
Y-intercept:(0,-5)
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Graph those two points.
{{{drawing( 300, 300, -10, 10, -10, 10,grid( 1 ),circle( 7,0, .4 ),
circle(0,-5,.4)))}}}
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Now draw the line connecting those two points and extend the line to the edges of your graph.
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{{{drawing( 300, 300, -10, 10, -10, 10,grid( 1 ),circle( 7,0, .4 ),
circle(0,-5,.4),green(line( -10, -12.14, 10, 2.14))))}}}