Question 23279
Is this the problem you had in mind:  {{{ h = (s-2*pi*r^2)/(2*pi*r) }}}for s?


If so, then first step is to multiply both sides of the equation by the denominator, which is {{{2*pi*r}}}:

{{{ h = (s-2*pi*r^2)/(2*pi*r) }}}
{{{(2*pi*r)* h =(2*pi*r)*((s-2*pi*r^2)/(2*pi*r)) }}}


The denominator divides out, leaving:
{{{2*pi*r* h =s-2*pi*r^2 }}}


Now, add {{{+2*pi*r^2}}} to each side of the equation, in order to get the s alone on the right side:
{{{2*pi*r* h =s-2*pi*r^2 }}}
{{{2*pi*r* h+2*pi*r^2  =s-2*pi*r^2 +2*pi*r^2 }}}
{{{2*pi*r* h+2*pi*r^2  =s }}}


R^2 at SCC