Question 163445
find three consecutive even integters such that five times the second equals twice the sum of the first and third 

Let the three integers be: x, x+2, x+4

then 5(x+2) = 2[x+(x+4)]

solve it:  5x + 10 = 2(2x + 4)

simplify 5x + 10 = 4x + 8

5x -4x = 8 - 10

x = -2

so the three integers are -2, 0, 2