Question 163389
an archer shoots an arrow into the air such that its height at any time, t, is given by the function h(t)= -16t.squared+ kt+ 3. If the maximum height of the arrow occurs at time t=4, what is the value of k?
:
We can use the axis of symmetry equation: x = {{{(-b)/(2*a)}}}
:
In this problem x = 4, a = -16, b = k
{{{(-k)/(2*-16)}}} = 4
{{{(-k)/(-32)}}} = 4
a minus into a minus is a plus
{{{k/32}}} = 4
Multiply both sides by 32
k = 32*4
k = 128