Question 163304
{{{x(x-2)=4}}}
{{{x^2-2x=4}}}
{{{x^2-2x-4=0}}}
Remember: {{{a=1,b=-2, c=-4}}}
By Pyth. theorem:
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
{{{x=(-(-2)+-sqrt(-2^2-4*1*-4))/(2*1)}}}
{{{x=(2+-sqrt(4+16))/2}}}
{{{x=(2+-sqrt(20))/2}}}
2 values:
{{{x=(2+sqrt(20))/2=(2+4.472136)/2=6.472136/2}}}
{{{highlight(x=3.236068)}}}
{{{x=(2-sqrt(20))/2=(2-4.72136)/2=-2.472136/2}}}
{{{x=-1.236068}}}
Check it out,{{{x=3.236068}}}
{{{3.236068(3.236068-2)=4}}}
{{{3.236068(1.236068)=4}}}
{{{4.000000001=4}}} close enough! bec of decimals
Thank you,
Jojo</pre>