Question 163207
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{{{C[1]}}}=30% orange
{{{C[2]}}}=5% orange
To get 25L, {{{C[1]+C[2]=25L}}} ----------------------------> eqn 1
In eqn 1 we get,
{{{C[2]=25-C[1]}}} -----------------------------------------> eqn 2
Also,
{{{0.30C[1]+0.05C[2]=25(0.10)}}} ---------------------------> eqn 3
Subst. eqn 2 in eqn 3,
{{{0.30C[1]+0.05(25-C[1])=2.50}}}
{{{0.30C[1]+1.25-0.05C[1]=2.50}}}
{{{0.25C[1]=2.50-1.25=1.25}}}
{{{cross(0.25)C[1]/cross(0.25)=cross(1.25)5L/cross(0.25)}}}
{{{highlight(C[1]=5L)}}}, 30% orange juice
And, via eqn 2: {{{highlight(C[2]=25-5=20L)}}}, 5% orange juice
In doubt? Go back eqn3 ,
{{{0.30*5+0.05*20=25*0.10}}}
{{{1.50+1=2.50}}}
{{{2.50=2.50}}}
Thank you,
Jojo</pre>