Question 163139
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{{{(2x-1)(3x+5)=5}}}
expand,(multiply)
{{{6x^2-3x+10x-5-5=0}}}
{{{6x^2+7x-10=0}}}
Remember ----{{{system(a=6,b=7,c=-10)}}}
By Quadratic:
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
{{{x=(-7+-sqrt(7^2-4*6*-10))/(2*6)}}}
{{{x=(-7+-sqrt(49+240))/12}}}
{{{x=(-7+-sqrt(289))/12=(-7+-17)/12}}}
2 values:
{{{x=(-7+17)/12=10/12=highlight(5/6)}}}
{{{x=(-7-17)/12=-24/12=highlight(-2)}}}
As it was shown right?
Thank you,
Jojo</pre>