Question 163030
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Take note of the following:
80% solt'n="x"
30% solt'n="y"
So, {{{x+y=750ml}}} -------------------------------> EQN 1
In EQN 1 we get, {{{x=750-y}}} --------------------> EQN 2
After the mixture,
{{{0.80x+0.30y=0.50(750ml)}}} ---------------------> EQN 3
Subst. EQN 2 in EQN 3:
{{{0.80(750-y)+0.30y=0.50(750)}}}
{{{600-0.80y=0.30y=375}}}
{{{600-375=0.80y-0.30y}}}
{{{225=0.50y}}} -----> {{{cross(225)450/cross(0.50)=cross(0.50)y/cross(0.50)}}}
{{{highlight(y=450ml)}}}, QUANTITY for the 30% solt'n.
Via EQN 2,
{{{x=750-450}}}
{{{highlight(x=300ml)}}}, QUANTITY for the 80% solt'n.
In doubt? Go back EQN 3,
{{{0.80(300)+0.30(450)=0.50(750)}}}
{{{240+135=375ml}}}
{{{375ml=375ml}}}
Thank you,
Jojo</pre>