Question 162989
Conjugate of 4-3i is 4+3i


{{{(4-3i)(4+3i)=(4)(4)+(4)(3i)+(-3i)(4)+(-3i)(3i)=16+12i-12i-9i^2=16-9i^2=16-(9)(-1)=16+9=25}}}



So {{{(4-3i)(4+3i)=25}}}